.NET[C#]Dapper中数据表的字段(列)与实体属性不一致时,如何手动配置它们之间的映射?
问题描述
比如有如下的数据表结构:
Person:
person_id int
first_name varchar(50)
last_name varchar(50)
以及实体类:
Person:
public class Person
{
public int PersonId { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
}
在C#程序中,使用Dapper做查询时,如何配置数据表字段(列)和实体类属性之间的映射呢?
方案一
var sql = @"select top 1 person_id PersonId, first_name FirstName, last_name LastName from Person";
using (var conn = ConnectionFactory.GetConnection())
{
var person = conn.Query<Person>(sql).ToList();
return person;
}
方案二
使用 ColumnAttribute 属性
完整的代码片段:
namespace YourNamespace
{
/// <summary>
/// Uses the Name value of the <see cref="ColumnAttribute"/> specified to determine
/// the association between the name of the column in the query results and the member to
/// which it will be extracted. If no column mapping is present all members are mapped as
/// usual.
/// </summary>
/// <typeparam name="T">The type of the object that this association between the mapper applies to.</typeparam>
public class ColumnAttributeTypeMapper<T> : FallbackTypeMapper
{
public ColumnAttributeTypeMapper()
: base(new SqlMapper.ITypeMap[]
{
new CustomPropertyTypeMap(
typeof(T),
(type, columnName) =>
type.GetProperties().FirstOrDefault(prop =>
prop.GetCustomAttributes(false)
.OfType<ColumnAttribute>()
.Any(attr => attr.Name == columnName)
)
),
new DefaultTypeMap(typeof(T))
})
{
}
}
[AttributeUsage(AttributeTargets.Property, AllowMultiple = true)]
public class ColumnAttribute : Attribute
{
public string Name { get; set; }
}
public class FallbackTypeMapper : SqlMapper.ITypeMap
{
private readonly IEnumerable<SqlMapper.ITypeMap> _mappers;
public FallbackTypeMapper(IEnumerable<SqlMapper.ITypeMap> mappers)
{
_mappers = mappers;
}
public ConstructorInfo FindConstructor(string[] names, Type[] types)
{
foreach (var mapper in _mappers)
{
try
{
ConstructorInfo result = mapper.FindConstructor(names, types);
if (result != null)
{
return result;
}
}
catch (NotImplementedException)
{
}
}
return null;
}
public SqlMapper.IMemberMap GetConstructorParameter(ConstructorInfo constructor, string columnName)
{
foreach (var mapper in _mappers)
{
try
{
var result = mapper.GetConstructorParameter(constructor, columnName);
if (result != null)
{
return result;
}
}
catch (NotImplementedException)
{
}
}
return null;
}
public SqlMapper.IMemberMap GetMember(string columnName)
{
foreach (var mapper in _mappers)
{
try
{
var result = mapper.GetMember(columnName);
if (result != null)
{
return result;
}
}
catch (NotImplementedException)
{
}
}
return null;
}
public ConstructorInfo FindExplicitConstructor()
{
return _mappers
.Select(mapper => mapper.FindExplicitConstructor())
.FirstOrDefault(result => result != null);
}
}
}
调用方法:
public class Person
{
[Column(Name="person_id")]
public int PersonId { get; set; }
[Column(Name="first_name")]
public string FirstName { get; set; }
[Column(Name="last_name")]
public string LastName { get; set; }
}
方案三
使用 CustomPropertyTypeMap 自定义属性类型映射类,如:
public class ColumnMap
{
private readonly Dictionary<string, string> forward = new Dictionary<string, string>();
private readonly Dictionary<string, string> reverse = new Dictionary<string, string>();
public void Add(string t1, string t2)
{
forward.Add(t1, t2);
reverse.Add(t2, t1);
}
public string this[string index]
{
get
{
// Check for a custom column map.
if (forward.ContainsKey(index))
return forward[index];
if (reverse.ContainsKey(index))
return reverse[index];
// If no custom mapping exists, return the value passed in.
return index;
}
}
}
配置列映射关系
var columnMap = new ColumnMap();
columnMap.Add("Field1", "Column1");
columnMap.Add("Field2", "Column2");
columnMap.Add("Field3", "Column3");
SqlMapper.SetTypeMap(typeof (MyClass), new CustomPropertyTypeMap(typeof (MyClass), (type, columnName) => type.GetProperty(columnMap[columnName])));
方案四
查询时使用LINQ
var sql = @"select top 1 person_id, first_name, last_name from Person";
using (var conn = ConnectionFactory.GetConnection())
{
List<Person> person = conn.Query<dynamic>(sql)
.Select(item => new Person()
{
PersonId = item.person_id,
FirstName = item.first_name,
LastName = item.last_name
}
.ToList();
return person;
}
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